Cho tam giác ABC có AB = 2, AC = 3. Gọi M là trung điểm của đoạn thẳng BC

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Top 1000 câu hỏi thường gặp môn Toán có đáp án (phần 22) hay nhất được biên soạn và chọn lọc giúp bạn ôn luyện và đạt kết quả cao trong bài thi môn Toán.

Cho tam giác ABC có AB = 2, AC = 3. Gọi M là trung điểm của đoạn thẳng BC

Câu 13: Cho tam giác ABC có AB = 2, AC = 3, stack text BAC end text with hat on top text  = 60° end text . Gọi M là trung điểm của đoạn thẳng BC. Điểm D thỏa mãn stack text AD end text with rightwards arrow on top text  =  end text fraction numerator text 7 end text over denominator text 12 end text end fraction stack text AC end text with rightwards arrow on top

a) Tính stack text AB end text with rightwards arrow on top text  .  end text stack text AC end text with rightwards arrow on top

b) Biểu diễn stack text AM end text with rightwards arrow on top text ,  end text stack text BD end text with rightwards arrow on top theo stack text AB end text with rightwards arrow on top text ,  end text stack text AC end text with rightwards arrow on top

c) Chứng minh A M text end text perpendicular text end text B D

Lời giải:

Top 1000 câu hỏi thường gặp môn Toán có đáp án (phần 22) (ảnh 2)

a) Ta có stack text AB end text with rightwards arrow on top text  .  end text stack text AC end text with rightwards arrow on top text  =  end text open vertical bar stack text AB end text with rightwards arrow on top close vertical bar text  .  end text open vertical bar stack text AC end text with rightwards arrow on top close vertical bar text  . cos end text open parentheses stack text AB end text with rightwards arrow on top text ,  end text stack text AC end text with rightwards arrow on top close parentheses text  =  2 . 3 . cos 60 end text to the power of text o end text end exponent text  = 3. end text

Vậy stack text AB end text with rightwards arrow on top text  .  end text stack text AC end text with rightwards arrow on top equals 3

b) Do M là trung điểm của BC nên stack text AM end text with rightwards arrow on top text  =  end text fraction numerator text 1 end text over denominator text 2 end text end fraction stack text AB end text with rightwards arrow on top text  +  end text fraction numerator text 1 end text over denominator text 2 end text end fraction stack text AC end text with rightwards arrow on top

Ta có stack text BD end text with rightwards arrow on top text  =  end text stack text AD end text with rightwards arrow on top text  -  end text stack text AB end text with rightwards arrow on top text  =  end text fraction numerator text 7 end text over denominator text 12 end text end fraction stack text AC end text with rightwards arrow on top text  -  end text stack text AB end text with rightwards arrow on top

c) Ta có stack text AM end text with rightwards arrow on top text  .  end text stack text BD end text with rightwards arrow on top text  =  end text open parentheses fraction numerator text 1 end text over denominator text 2 end text end fraction stack text AB end text with rightwards arrow on top text  +  end text fraction numerator text 1 end text over denominator text 2 end text end fraction stack text AC end text with rightwards arrow on top close parentheses text  .  end text open parentheses fraction numerator text 7 end text over denominator text 12 end text end fraction stack text AC end text with rightwards arrow on top text  -  end text stack text AB end text with rightwards arrow on top close parentheses

text =  end text fraction numerator text 7 end text over denominator text 24 end text end fraction stack text AB end text with rightwards arrow on top text  .  end text stack text AC end text with rightwards arrow on top text  -  end text fraction numerator text 1 end text over denominator text 2 end text end fraction stack text AB end text with rightwards arrow on top to the power of text 2 end text end exponent text  +  end text fraction numerator text 7 end text over denominator text 24 end text end fraction stack text AC end text with rightwards arrow on top to the power of text 2 end text end exponent text  -  end text fraction numerator text 1 end text over denominator text 2 end text end fraction stack text AC end text with rightwards arrow on top text  .  end text stack text AB end text with rightwards arrow on top
text =  end text fraction numerator text 7 end text over denominator text 24 end text end fraction text  . 3 -  end text fraction numerator text 1 end text over denominator text 2 end text end fraction text  . 2 end text to the power of text 2 end text end exponent text  +  end text fraction numerator text 7 end text over denominator text 24 end text end fraction text  . 3 end text to the power of text 2 end text end exponent text  -  end text fraction numerator text 1 end text over denominator text 2 end text end fraction text  . 3 = 0 end text

Do đó A M perpendicular B D.

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